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Library / Electrical / ELE-26

Electrical

Series RLC impedance

Total opposition to alternating current in a series circuit.

Ref
ELE-26
Rev
v1
Field
Electrical
Result
Z [Ω]

R is the resistance, XL = ωL the inductive reactance and XC = 1/(ωC) the capacitive reactance, all in ohms at the operating frequency. Because the two reactances are 180° apart in phase, they subtract. Z is the size of the total opposition; the current is I = V/Z.

Total opposition to alternating current in a series circuit. The reactances partly cancel; at resonance they cancel fully and only R is left.

Calculator

Solve for
Ω
Ω
0.11,000
Ω
01,000
Ω
01,000
  • Net reactance XL − XC40 Ω
  • Phase angle of the voltage ahead of the current53.13 °

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

Impedance (Ω) current value 50 Ω
RResistanceKey driver
401,000
XLInductive reactance
30.2970
XCCapacitive reactance
30.2930
  • The defaults give a 30-40-50 triangle: R = 30 Ω, net reactance 40 Ω, Z = 50 Ω. The voltage leads the current by 53°, so the circuit looks inductive.
  • When XL = XC the reactance cancels completely, Z falls to its minimum R, and the current peaks: that is resonance.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing (Ω)Local stepChange in result
R Resistance0.1 to 1,000 Ω401,001960.8+10%+3.71 %
XL Inductive reactance0 to 1,000 Ω30.18970.5940.3+10%+11.5 %
XC Capacitive reactance0 to 1,000 Ω30.18930.5900.3+10%−4.73 %

Sweep of Capacitive reactance

Capacitive reactance (Ω)Impedance (Ω)
076.16
12562.65
250182.5
375306.5
500431
625555.8
750680.7
875805.6
1,000930.5

Sweep one variable

Impedance (Ω)Hover, touch, or use the arrow keys on the chart
02004006008001000 02004006008001000 Capacitive reactance (Ω) now 50

Variables and how each one contributes

Z

Impedance

Result · Ω

What the equation gives you. Everything else feeds it.

R

Resistance

Ω · typical 0.1 to 1,000

The resistance of the circuit. Matters more when the net reactance is small. At the default a 10 % rise in R (3 Ω) raises Z by about 3.7 %; at resonance Z equals R.

XL

Inductive reactance

Ω · typical 0 to 1,000

The inductive reactance, which rises with frequency. Raises Z when XL is above XC. A 10 % rise in XL (7 Ω) raises Z by about 11.5 %, the strongest lever here, because it widens the net reactance.

XC

Capacitive reactance

Ω · typical 0 to 1,000

The capacitive reactance, which falls with frequency. Lowers Z while XC is below XL, because it cancels part of the inductive reactance: a 10 % rise (3 Ω) lowers Z by about 4.7 %. Past XL it raises Z again.

Worked example with the values above

  1. Net reactance: XL − XC = 70 − 30 = 40 Ω.
  2. Squares: R² + (XL − XC)² = 900 + 1,600 = 2,500.
  3. Z = √2,500 = 50 Ω.

Assumptions and limits

  • A single frequency, steady-state sine wave, with linear components.
  • R, L and C connected in series, with ideal inductor and capacitor.

Common mistakes

  • Adding XL and XC instead of subtracting them.
  • Adding R and the reactance directly instead of in quadrature.

Statistics and uncertainty

Z is the square root of a sum of squares, so the larger of R and the net reactance dominates. Near resonance the small net reactance is a difference of two large numbers and is very sensitive: a 1 % mismatch between two 1000 Ω reactances leaves 10 Ω of net reactance, which can exceed R.

Where it is used

  • Finding the current drawn by a tuned circuit or filter.
  • Choosing a capacitor to cancel an inductive load.

Maths you need

  • Reactance: XL = ωL, XC = 1/ωC
  • Pythagoras: combining at right angles

Related formulas

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